Balancing Chemical Reactions and Atoms

The video tutorial explains the process of balancing a chemical equation involving hydrofluoric acid (HF) and magnesium hydroxide (Mg(OH)2). It begins with identifying the reactants and products, then counts the atoms on each side of the equation. The tutorial demonstrates how to balance the equation by adjusting coefficients, ensuring the number of atoms for each element is equal on both sides. The final balanced equation is HF + Mg(OH)2 yields MgF2 + H2O.

What type of reaction occurs when HF reacts with Mg(OH)2?

• Combustion

• Neutralization

• Decomposition

• Synthesis

What are the products formed in the reaction between HF and Mg(OH)2?

• MgF2 and H2O

• MgO and H2

• HF and Mg(OH)2

• H2 and O2

How many hydrogen atoms are present on the reactant side initially?

• 4

• 3

• 2

• 5

What is the initial imbalance in the number of fluorine atoms on the product side?

• 3

• 1

• 2

• 4

What coefficient is added in front of HF to balance the fluorine atoms?

• 3

• 1

• 4

• 2

After balancing fluorine, how many hydrogen atoms are there on the reactant side?

• 2

• 3

• 4

• 5

What coefficient is used in front of water to balance the hydrogen atoms?

• 4

• 3

• 1

• 2

How many oxygen atoms are present on each side after balancing?

• 1

• 2

• 3

• 4

What is the final balanced equation for the reaction?

• 2HF + Mg(OH)2 → MgF2 + 2H2O

• HF + Mg(OH)2 → MgF2 + H2O

• 2HF + MgO → MgF2 + H2

• HF + MgO → MgF2 + H2O