Lead Compounds and Ionic Charges

The video tutorial explains how to write the formula for lead(II) fluoride by examining the periodic table to identify the elements involved: lead (Pb) and fluorine (F). It discusses the ionic charges of these elements, with lead having a 2+ charge and fluorine a 1- charge. The tutorial demonstrates using the crisscross method to balance these charges and derive the correct formula, PbF2. The video concludes by verifying the formula to ensure a net charge of zero, confirming the accuracy of the derived formula.

What is the element symbol for lead?

• F

• Pb

• L

• Le

Why is lead(II) considered an ionic compound?

• Because it involves a metal and a nonmetal

• Because it is made of two metals

• Because it is a compound of two nonmetals

• Because it is a compound of two gases

What does the Roman numeral in lead(II) indicate?

• The number of lead atoms

• The atomic number of lead

• The ionic charge of lead

• The number of fluorine atoms

What is the charge on a fluorine ion?

• 1+

• 2+

• 2-

• 1-

How do you achieve a net charge of zero in lead(II) fluoride?

• By changing the state of lead

• By removing fluorine atoms

• By balancing the charges of lead and fluorine

• By adding more lead atoms

What method is used to determine the formula for lead(II) fluoride?

• Addition method

• Substitution method

• Crisscross method

• Balancing method

How many fluorine ions are needed to balance one lead ion in lead(II) fluoride?

• One

• Two

• Three

• Four

What is the net charge of lead(II) fluoride?

• 0

• 1+

• 2-

• 3+

What is the final chemical formula for lead(II) fluoride?

• Pb2F

• Pb2F2

• PbF2

• PbF