Solve Quadratic Equations by Zero Product Property

Solve for the values of x.

(x + 2)(x - 3) = 0

• { 2, 3 }

• { -2, -3 }

• { 2, 3 }

• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

• -6, -2
• -2, 6
• 2, 6
• -6, 2

Tags

CCSS.HSA-REI.B.4B

Use the zero product property to find the solutions to the equation 6x²-5x=56

• x = -8 or x = 7/6

• x = -8/3 or x = 7/2

• x = -1/2 or x = 56/3

• x = -3/7 or x = 2/3

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown.

• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B

What are the zeros of the function below?
(x - 6)(2x + 4) =0

• x = -6, x = -4

• x = 6, x = -2

• x = 4, x = 6, x =2

• cannot be determined

Tags

CCSS.HSF-IF.C.7C

• -4, 2
• -2, 4
• -16
• -4

Tags

CCSS.HSA-REI.B.4B

In the equation
 (x + 2)(x - 3) = 0, the binomials are called...?

• Factors

• Products

• Multiples

• Zeros

Tags

CCSS.HSA.APR.B.2

Find the values for n.

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below: x² + 4x - 12 = 2 (x - 2)(x + 6) = 2, by setting x -2 = 0 and x + 6 = 0. Her solutions are x = 2 and x = -6. Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property

• Yes, she factored correctly and then square rooted.

• No, she did factor correctly, but she can't use the zero product property as shown. She needed to set equation equal to zero.

• No, she didn't factor correctly so the rest of her work is wrong.

Tags

CCSS.HSA-REI.B.4B

What are the solutions?

• -2, 4

• -8

• ±8

• No real solution

Tags

CCSS.HSA-REI.B.4B