Mole Conversions Practice Quiz

How many molecules are there in 21.6 grams of CH₄ (molar mass = 16.04 g/mol)?

• 8.10 x 10²³ molecules

• 8.10 x 10⁴⁶ molecules

• 2.24 x 10^-24 molecules

• 1.35 molecules

To find the number of grams in 1.2 moles of Sodium chloride, you would

• Multiply by 6.02 x 10²³

• Divide by 6.02 x 10²³

• Multiply by the mass of NaCl

• Divide by the mass of NaCl

Answer explanation

This is a two step. Divide by molecular weight of CH₄ and multiply by Avagadro's number.

To find the number of moles in a sample if given mass, you would

• Multiply by 6.02 x 10²³

• Divide by 6.02 x 10²³

• Multiply by the atomic/molar mass

• Divide by the atomic/molar mass

Calculate the mass of 9.0 moles of carbon.

• 108.1 g

• 0.75 g

• 5.42 x 10²⁴ g

• 6.51 x 10²³ g

What is the molar mass of Sodium bicarbonate (NaHCO₃)?

• 84.02 g/mol

• 52.02 g/mol

• 5.1 x 10²³ g/mol

• 62.0 g/mol

Calculate the number of moles in 127 g of H₂SO₄.

• 1.29 moles

• 7.7 x 10²³ moles

• 2.59 moles

• 127 moles

Tags

NGSS.HS-PS1-7

To convert between moles and number of particles, you would use _____________ while to convert between moles and mass, you would use ____________.

• Molar mass, molar mass

• Avogadro’s number, molar mass

• Molar mass, Avogadro’s number

• 
  Avogadro’s number, Avogadro’s number

Rank the following from highest to lowest by number of particles: 1 mole copper, 1 mole aluminum, 1 mole of water, 1 mole of baking soda (NaHCO₃).

• Copper, aluminum, water, baking soda

• Baking soda, water, aluminum, copper

• Water, copper, aluminum, baking soda

• They all have the same number of particles

Rank the following from highest to lowest by atomic/molar mass: 1 mole copper, 1 mole aluminum, 1 mole of water, 1 mole of baking soda (NaHCO₃).

• Copper, aluminum, water, baking soda

• Baking soda, water, aluminum, copper

• Baking soda, copper, aluminum, water

• They all have the mass

To answer the question: a 39 g portion of LiF contains how many moles, you would

• Multiple by 6.02 x 10²³

• Divide by 6.02 x 10²³

• Multiply by molar mass of LiF

• 
  Divide by molar mass of LiF