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Algebra I EOC: Unit 2 Linear Equations & Inequalities

Authored by Heidi Arwood

Mathematics

8th - 9th Grade

CCSS covered

Used 16+ times

Algebra I EOC: Unit 2 Linear Equations & Inequalities
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25 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

This equation can be used to find h, the number of hours it will take Flo and Bryan to mow their lawn.  h3+h6=1\frac{h}{3}+\frac{h}{6}=1   How many hours will it take them to mow their lawn?

6

3

2

1

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

A ferry boat carries passengers back and forth between two communities on the Peachville River.

 • It takes 30 minutes longer for the ferry to make the trip upstream than downstream. 

• The ferry’s average speed in still water is 15 miles per hour. 

• The river’s current is usually 5 miles per hour. 

This equation can be used to determine how many miles apart the two communities are. 

 m155=m15+5+0.5\frac{m}{15-5}=\frac{m}{15+5}+0.5  

What is m, the distance between the two communities?

0.5 miles

5 miles

10 miles 

15 miles 

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 23 +x3>1\frac{2}{3\ }+\frac{x}{3}>1  

For what values of x is the inequality true? 

x<1

x>1

x<5

x>5

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Look at the steps used when solving 3(x – 2) = 3 for x.


3(x – 2) = 3 (Write the original equation).


3x – 6 = 3 (Use the Distributive Property).


3x – 6 + 6 = 3 + 6 (Step 1)


3x = 9 (Step 2)


3x ___ 3 = 9__ 3 (Step 3)


x = 3 (Step 4)


Which step is the result of combining like terms?

Step 1

Step 2

Step 3

Step 4

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

A wild horse runs at a rate of 8 miles an hour for 6 hours. Let y be the distance, in miles, the horse travels for a given amount of time, x, in hours. This situation can be modeled by a function.


Which of these describes the domain of the function?

0 ≤ x ≤ 6

0 ≤ y ≤ 6

0 ≤ x ≤ 48

0 ≤ y ≤ 48

6.

MULTIPLE CHOICE QUESTION

1 min • 12 pts

 2v + v = 3-2v\ +\ v\ =\ 3  

4

5-5

3-3

5

Tags

CCSS.7.EE.B.4A

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 96=6(k+8)96=6\left(k+8\right)  

 1212  

 88  

 4-4  

 99  

Tags

CCSS.7.EE.B.4A

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