Calculus 1.6 Trigonometry Review

Cos^-1(√3/2) = 

• π/3
• 2π/3
• π/6
• 5π/6

What range of angles can you get from the value of inverse sine?

• 0 to π

• 0 to 2π

• -π/2 to π/2

• π/2 to 3 π/2

Arcsin (-1) (this is the same as sin^-1(-1)

• π/2

• -1

• -π/2

• 1

What is the correct ratio?

• 20/12
• 12/20
• 12/16
• 16/12

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Which is the correct applied ratio?

• A

• B

• C

• D

Tags

CCSS.HSG.SRT.C.6

Simplify.

• csc²θ
• sec²θ
• cscθ
• 1

Simplify.

• sinθ
• cos²θ
• sin²θ
• 1- sin²θ

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.TF.C.8

Solve on the domain [0, 2π)
cos² x + sin x + 1 = 0

• π
• 3π/2
• π/6, 5π/6, 3π/2
• No solution

Tags

CCSS.HSA.REI.B.4

CCSS.HSF.TF.A.2

CCSS.HSF.TF.A.4

Solve on the domain [0, 2π)
2sin x cos x = √2 cos x

• π/2, 3π/2
• 0, π/4, 3π/4
• π/2, 3π/2, π/4, 3π/4
• No solution

Tags

CCSS.HSA.REI.B.4

CCSS.HSF.TF.A.3

CCSS.HSF.TF.A.4

CCSS.HSF.TF.B.7

To solve this equation, cos²x + sinx = 1, replace cos²x with

• 1/(sec²x)

• sin²x − 1

• 1 − sin²x

• 1 + tan²x

Tags

CCSS.HSF.TF.C.8