Net Ionic Equations and Ion Charges

The video tutorial explains how to write a net ionic equation for the reaction between potassium sulfate and barium nitrate. It begins with balancing the molecular equation, then determining the states of the compounds using solubility rules. The tutorial continues by identifying ion charges and splitting compounds into ions. Finally, it demonstrates how to form the net ionic equation by removing spectator ions, concluding with the finalized equation.

What is the first step in writing a net ionic equation?

• Write the net ionic equation directly

• Determine the solubility of compounds

• Balance the molecular equation

• Identify spectator ions

Which compound is insoluble and forms a precipitate in the reaction?

• Barium nitrate

• Potassium sulfate

• Barium sulfate

• Potassium nitrate

What is the role of a solubility table in this reaction?

• To determine the charges of ions

• To identify spectator ions

• To check the solubility of compounds

• To balance the equation

What is the charge of the sulfate ion?

• 1-

• 2+

• 2-

• 1+

What is the charge of the barium ion?

• 1+

• 2+

• 1-

• 2-

What is the charge of the nitrate ion?

• 1-

• 2+

• 1+

• 2-

Which ions are considered spectator ions in this reaction?

• Potassium and nitrate ions

• Barium and sulfate ions

• Only potassium ions

• Only nitrate ions

What happens to spectator ions in the net ionic equation?

• They are included in the equation

• They change their charge

• They are removed from the equation

• They form a precipitate

What is the final product of the net ionic equation?

• Potassium sulfate

• Barium nitrate

• Barium sulfate

• Potassium nitrate

Why do we not split solids into ions in net ionic equations?

• They are spectator ions

• They dissolve completely

• They are insoluble and remain intact

• They are not reactive