Oxidation Numbers and Compounds

The video tutorial explains how to find the oxidation numbers for phosphorus in P4O10. It begins by clarifying that P2O5 does not exist and introduces the structure of P4O10. The tutorial then details the process of calculating the oxidation numbers, starting with the known oxidation state of oxygen (-2) and using algebra to determine that each phosphorus atom has an oxidation number of +5. The video concludes by summarizing the findings and reiterating the non-existence of P2O5.

Which compound is often mistakenly thought to exist but actually doesn't?

• P2O10

• P4O10

• P4O5

• P2O5

How many oxygen atoms are present in the compound P4O10?

• 5

• 8

• 10

• 4

What is the oxidation number of oxygen in most compounds?

• +2

• -2

• 0

• +1

In the compound P4O10, what is the oxidation number of phosphorus?

• +1

• +7

• +5

• +3

What is the total negative charge contributed by oxygen atoms in P4O10?

• -10

• -20

• -40

• -5

What is the algebraic expression used to calculate the oxidation number of phosphorus in P4O10?

• 4X + 10 = 0

• 4X + 20 = 0

• 4X - 20 = 0

• 4X - 10 = 0

What is the significance of the average oxidation number in P4O10?

• It only applies to oxygen atoms.

• It is the same for all phosphorus atoms.

• It varies for each phosphorus atom.

• It is not applicable.