Balancing Chemical Equations Practice

The video tutorial demonstrates how to balance a chemical equation involving lead nitrate and potassium iodide. It begins by counting the atoms on both sides of the equation, identifying imbalances, and then adjusting coefficients to achieve balance. The process involves balancing nitrate ions first, followed by potassium and iodine atoms. The tutorial concludes with a balanced equation and a brief recap.

What is the initial chemical equation discussed in the video?

• Magnesium sulfate plus barium chloride yields barium sulfate plus magnesium chloride

• Calcium carbonate plus hydrochloric acid yields calcium chloride plus carbon dioxide

• Sodium chloride plus silver nitrate yields silver chloride plus sodium nitrate

• Lead nitrate plus potassium iodide yields potassium nitrate plus lead iodide

How many nitrate ions are initially present on the reactant side?

• Two

• One

• Three

• Four

What adjustment is made to balance the nitrate ions?

• Add a coefficient of 3 in front of KI

• Add a coefficient of 2 in front of Pb(NO3)2

• Add a coefficient of 3 in front of PbI2

• Add a coefficient of 2 in front of KNO3

After balancing the nitrates, what is the next element to be balanced?

• Lead

• Iodine

• Potassium

• Oxygen

What coefficient is added in front of KI to balance the potassium atoms?

• 4

• 1

• 2

• 3

How many iodine atoms are present on the product side after balancing?

• Three

• One

• Four

• Two

What is the final balanced chemical equation?

• Pb(NO3)2 + KI → KNO3 + PbI2

• Pb(NO3)2 + KI → 2KNO3 + PbI2

• Pb(NO3)2 + 2KI → 2KNO3 + PbI2

• 2Pb(NO3)2 + KI → KNO3 + 2PbI2