Balancing Chemical Equations Practice

The video tutorial explains how to balance a chemical equation involving calcium chloride and sodium phosphate. It begins by counting the atoms on both the reactant and product sides, emphasizing the importance of keeping the phosphate ion together. The tutorial then demonstrates the step-by-step process of balancing the equation by adjusting coefficients to ensure the same number of each type of atom on both sides. The video concludes with the final balanced equation and highlights the simplification achieved by treating phosphate as a single unit.

What is the initial number of calcium atoms on the reactant side of the equation?

• Four

• One

• Three

• Two

Why are phosphorus and oxygen atoms kept together in the balancing process?

• They form a stable compound

• They are easier to count separately

• They are part of the phosphate ion

• They do not react with other elements

How many calcium atoms are present on the product side before balancing?

• One

• Two

• Three

• Four

What coefficient is placed in front of calcium chloride to balance the calcium atoms?

• 4

• 3

• 2

• 1

How many chlorine atoms are there on the reactant side after balancing calcium?

• Four

• Two

• Eight

• Six

What coefficient is used in front of NaCl to balance the chlorine atoms?

• 4

• 8

• 2

• 6

How many sodium atoms are there on the reactant side after balancing?

• Twelve

• Nine

• Six

• Three

What coefficient is placed in front of sodium phosphate to balance the sodium atoms?

• 1

• 4

• 2

• 3

How many phosphate ions are present on the product side after balancing?

• Three

• Four

• Two

• One

What is the final balanced chemical equation?

• CaCl2 + 2Na3PO4 → 3Ca3(PO4)2 + NaCl

• 3CaCl2 + Na3PO4 → Ca3(PO4)2 + 6NaCl

• CaCl2 + Na3PO4 → Ca3(PO4)2 + NaCl

• 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl