Balancing Chemical Equations

The video tutorial demonstrates how to balance the chemical equation S8 + O2 → SO3. It begins by counting the sulfur and oxygen atoms on both sides of the equation. The instructor then explains how to balance the sulfur atoms by placing a coefficient of 8 in front of SO3, resulting in 8 sulfur atoms on both sides. This adjustment also affects the oxygen atoms, leading to 24 oxygen atoms on the product side. To balance the oxygen atoms, a coefficient of 12 is placed in front of O2, ensuring both sides have 24 oxygen atoms. The video concludes with the balanced equation: S8 + 12O2 → 8SO3.

What is the initial number of sulfur atoms on the reactant side of the equation S8 + O2 → SO3?

• 16

• 8

• 2

• 1

How many sulfur atoms are present on the product side before balancing?

• 1

• 16

• 2

• 8

What coefficient is placed in front of SO3 to balance the sulfur atoms?

• 8

• 2

• 4

• 6

After balancing sulfur, how many oxygen atoms are on the product side?

• 24

• 32

• 16

• 12

What is the coefficient in front of O2 to balance the oxygen atoms in the equation?

• 12

• 8

• 6

• 10