Balancing Chemical Equations Practice

This video tutorial demonstrates how to balance the chemical equation ZnCl2 + Na2CO3. It begins by counting the atoms on each side of the equation, noting the presence of zinc, chlorine, sodium, and the carbonate ion. The tutorial explains that the carbonate ion remains intact during the reaction. To balance the equation, the video suggests doubling the chlorines and sodiums by placing a coefficient of 2 in front of NaCl. This adjustment ensures that the number of atoms on both sides of the equation is equal, resulting in a balanced equation. The video concludes with a summary of the balanced equation and thanks viewers for watching.

What is the initial number of chlorine atoms on the reactant side of the equation ZnCl2 + Na2CO3?

• One

• Four

• Two

• Three

What is the role of the carbonate ion in the reaction?

• It reacts with sodium.

• It remains intact throughout the reaction.

• It combines with zinc.

• It breaks down into separate elements.

How many sodium atoms are needed on the product side to balance the equation?

• Three

• One

• Two

• Four

What coefficient is placed in front of NaCl to balance the equation?

• 1

• 2

• 4

• 3

What is the final number of chlorine atoms on the product side after balancing?

• One

• Two

• Three

• Four

Which element's atoms are doubled to achieve balance in the equation?

• Carbon

• Chlorine

• Zinc

• Oxygen

What is the final balanced equation for ZnCl2 + Na2CO3?

• 2ZnCl2 + Na2CO3 → ZnCO3 + 2NaCl

• ZnCl2 + 2Na2CO3 → ZnCO3 + NaCl

• ZnCl2 + Na2CO3 → ZnCO3 + NaCl

• ZnCl2 + Na2CO3 → ZnCO3 + 2NaCl