Ionic Reactions and Compounds

This video tutorial explains how to write the net ionic equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4). It covers the identification of ion charges, prediction of products, balancing the molecular equation, and determining the states of compounds. The tutorial also demonstrates how to write the complete and net ionic equations by identifying and removing spectator ions. The video concludes with a summary of the net ionic equation.

What type of reaction occurs between potassium hydroxide and sulfuric acid?

• Decomposition

• Synthesis

• Single displacement

• Neutralization

What is the charge of the potassium ion in the reaction?

• 2+

• 1+

• 1-

• 2-

Which ion pairs with sulfate in the product of the reaction?

• Hydroxide

• Oxygen

• Hydrogen

• Potassium

What is the balanced formula for potassium sulfate?

• KSO3

• K2S

• K2SO4

• KSO4

What state is water in during the reaction?

• Liquid

• Solid

• Aqueous

• Gas

What is the state of K2SO4 in the reaction?

• Solid

• Liquid

• Gas

• Aqueous

What is the purpose of splitting soluble compounds into ions?

• To form the complete ionic equation

• To identify the products

• To simplify the equation

• To balance the equation

Which ions are considered spectator ions in this reaction?

• Sulfate and hydroxide

• Potassium and hydrogen

• Potassium and sulfate

• Hydrogen and hydroxide

What is the net ionic equation for the reaction?

• H+ + OH- → H2O

• 2K+ + SO4 2- → K2SO4

• 2H+ + 2OH- → 2H2O

• KOH + H2SO4 → K2SO4 + H2O

What is the final product formed along with potassium sulfate in the reaction?

• Water

• Oxygen

• Hydrogen gas

• Sulfur dioxide