Net Ionic Equations and Spectator Ions

The video tutorial explains how to write the net ionic equation for the reaction between strontium chloride (SrCl2) and sodium carbonate (Na2CO3). It begins with balancing the molecular equation, then determining the states of each substance. The tutorial proceeds to break down strong electrolytes into ions to form the complete ionic equation. Spectator ions are identified and removed to derive the net ionic equation, which highlights the formation of a solid precipitate, strontium carbonate (SrCO3). The video concludes with a tidy presentation of the net ionic equation.

What is the first step in writing a net ionic equation?

• Write the complete ionic equation

• Identify spectator ions

• Balance the molecular equation

• Determine the solubility of compounds

Which of the following compounds is generally soluble in water?

• Strontium carbonate

• Lead(II) iodide

• Sodium chloride

• Calcium sulfate

Why is strontium carbonate considered a solid in the reaction?

• It is a gas at room temperature

• It is a liquid at room temperature

• It forms a precipitate

• It is highly soluble in water

What is the charge of the strontium ion in the reaction?

• 2-

• 1+

• 1-

• 2+

What is the charge of the carbonate ion?

• 1+

• 2+

• 2-

• 1-

Which ion is considered a spectator ion in this reaction?

• Strontium carbonate

• Sodium ion

• Carbonate ion

• Strontium ion

Which of the following is NOT a step in deriving the net ionic equation?

• Combining all ions into one equation

• Identifying spectator ions

• Balancing the molecular equation

• Writing the complete ionic equation

What happens to spectator ions in the net ionic equation?

• They are included in the final equation

• They are removed from the equation

• They change their charge

• They form a new compound

What is the net ionic equation for the reaction between strontium chloride and sodium carbonate?

• Sr2+ + 2Cl- + 2Na+ + CO3 2- → SrCO3 + 2Na+ + 2Cl-

• Sr2+ + CO3 2- → SrCO3

• 2Na+ + 2Cl- → 2NaCl

• SrCl2 + Na2CO3 → SrCO3 + 2NaCl

What is the purpose of writing a net ionic equation?

• To show all compounds involved

• To highlight the formation of precipitates

• To balance the charges in the equation

• To focus on the ions that participate in the reaction