Net Ionic Equations and Spectator Ions

This video tutorial explains how to balance the net ionic equation for lead(II) acetate reacting with sodium sulfide. It begins by balancing the molecular equation, then determines the states of each substance, identifying which are soluble or insoluble. The tutorial proceeds to split strong electrolytes into ions for the complete ionic equation and identifies spectator ions to derive the net ionic equation. The video concludes by ensuring charge and mass balance in the final equation.

What is the first step in balancing a net ionic equation?

• Balance the molecular equation

• Identify spectator ions

• Determine the solubility of compounds

• Split compounds into ions

Which of the following is generally soluble in water?

• Carbonate compounds

• Lead compounds

• Sodium compounds

• Sulfide compounds

What happens to lead sulfide in the reaction?

• It reacts with sodium

• It remains as ions

• It forms a precipitate

• It dissolves in water

What is the charge of the acetate ion?

• 1+

• 2+

• 1-

• 2-

What is the charge of the lead ion in this reaction?

• 2+

• 2-

• 1+

• 1-

Why do we not split solids in net ionic equations?

• They do not dissociate into ions

• They are spectator ions

• They are always reactants

• They are insoluble

What is the purpose of identifying spectator ions?

• To balance the equation

• To simplify the net ionic equation

• To determine solubility

• To find the limiting reactant

Which ion is a spectator ion in the reaction between lead(II) acetate and sodium sulfide?

• Acetate ion

• Sulfide ion

• Sodium ion

• Lead ion

What is the final step in balancing a net ionic equation?

• Identify spectator ions

• Ensure charge and mass conservation

• Determine solubility

• Split compounds into ions

What is conserved in a balanced net ionic equation?

• Neither mass nor charge

• Both mass and charge

• Only charge

• Only mass