Oxidation Numbers in Compounds

The video tutorial explains how to find the oxidation numbers for each element in the compound CaCrO4. It starts by identifying the compound as neutral, meaning the oxidation numbers must sum to zero. Calcium, being in group 2, has a +2 oxidation number, while oxygen is typically -2. The tutorial then focuses on determining the oxidation number for chromium by setting up an equation. The solution shows that chromium has an oxidation number of +6. The video concludes with a summary of the findings.

What is the oxidation number of calcium in CaCrO4?

• +1

• +2

• +3

• +4

Why do the oxidation numbers in a neutral compound like CaCrO4 add up to zero?

• Because it is a rule for all compounds

• Because it is a rule for ionic compounds

• Because the compound has no net charge

• Because it is a rule for covalent compounds

What is the typical oxidation number of oxygen in compounds?

• -1

• -2

• -3

• 0

How do you determine the oxidation number of chromium in CaCrO4?

• By assuming it is zero

• By assuming it is the same as calcium

• By using the known oxidation numbers of calcium and oxygen

• By using the periodic table

What equation can be set up to find the oxidation number of chromium in CaCrO4?

• x - 2 = 0

• x + 4 = 0

• x - 6 = 0

• x + 2 = 0

What is the oxidation number of chromium in CaCrO4?

• +6

• +5

• +4

• +7