Oxidation Numbers in Compounds

This video tutorial explains how to determine the oxidation numbers for each element in sodium sulfate (Na2SO4). It begins by discussing the neutrality of the compound and the known oxidation number of sodium. The video then explores the variable oxidation number of sulfur and the constant oxidation number of oxygen. An equation is set up to solve for sulfur's oxidation number, resulting in a value of +6. The tutorial concludes with a recap of the oxidation numbers for all elements in Na2SO4.

What does the absence of a charge sign after sodium sulfate indicate about the compound?

• It is an unstable compound.

• It is a negatively charged compound.

• It is a positively charged compound.

• It is a neutral compound.

Which group on the periodic table does sodium belong to, and what is its typical oxidation number?

• Group 3, +3

• Group 1, +1

• Group 2, +2

• Group 4, +4

Why is the oxidation number of sulfur initially unknown in sodium sulfate?

• Sulfur's oxidation number is always zero.

• Sulfur is not present in sodium sulfate.

• Sulfur's oxidation number varies depending on its bonds.

• Sulfur always has a fixed oxidation number.

What is the typical oxidation number for oxygen in compounds?

• -3

• -2

• 0

• -1

How is the equation set up to solve for the oxidation number of sulfur in sodium sulfate?

• 2 + x + 4(-2) = 0

• 2x + 4(-2) = 0

• 2 + 4x = 0

• x + 4(-2) = 0

What is the oxidation number of sulfur in sodium sulfate after solving the equation?

• +4

• +5

• +6

• +7

What is the sum of all oxidation numbers in a neutral compound like sodium sulfate?

• +2

• -1

• 0

• +1

How do the oxidation numbers of sodium, sulfur, and oxygen in sodium sulfate add up to confirm neutrality?

• 2(+1) + 1(+7) + 4(-2) = 0

• 2(+1) + 1(+5) + 4(-2) = 0

• 2(+1) + 1(+4) + 4(-2) = 0

• 2(+1) + 1(+6) + 4(-2) = 0