Net Ionic Equations and Solubility

The video tutorial explains how to write a balanced net ionic equation for the reaction between copper(II) chloride and ammonium sulfide. It begins with balancing the molecular equation, followed by determining the solubility and states of the substances involved. The tutorial then demonstrates how to split strong electrolytes into ions to form the complete ionic equation. Finally, it identifies and removes spectator ions to derive the net ionic equation, ensuring charge and atom balance.

What is the first step in writing a balanced net ionic equation?

• Identify spectator ions

• Balance the molecular equation

• Determine the solubility of compounds

• Write the complete ionic equation

Which compound is used in the video as an example of a transition metal?

• Copper(II) chloride

• Ammonium sulfide

• Sodium chloride

• Potassium nitrate

How do you balance the molecular equation for copper(II) chloride and ammonium sulfide?

• Adjust the coefficients to balance atoms

• Change the state of the compounds

• Add more ammonium ions

• Add more copper ions

What is the solubility rule for chlorides mentioned in the video?

• Insoluble

• Soluble only in hot water

• Very soluble

• Slightly soluble

What happens to copper(II) sulfide in the reaction?

• It reacts with ammonium ions

• It remains as ions

• It forms a precipitate

• It dissolves in water

What is the charge on the copper ion in the complete ionic equation?

• 0

• 3+

• 2+

• 1+

Why don't we split solids in net ionic equations?

• They are not strong electrolytes

• They do not dissociate into ions

• They are spectator ions

• They are already balanced

What are spectator ions?

• Ions that form a precipitate

• Ions that are insoluble

• Ions that do not change during the reaction

• Ions that participate in the reaction

What is the net charge of the balanced net ionic equation?

• 1+

• 0

• 2-

• 2+

What ensures the net ionic equation is correctly balanced?

• Equal number of atoms on both sides

• Equal number of molecules on both sides

• Equal number of compounds on both sides

• Equal number of electrons on both sides