Valence Electrons and Molecular Geometry of AlI3

The video tutorial explains how to write the Lewis structure for aluminum iodide (AlI3). It begins by counting the valence electrons: aluminum has three, and each iodine has seven, totaling 24 valence electrons. Aluminum, being the least electronegative, is placed in the center with iodine atoms around it. The video discusses the octet rule, noting that aluminum is an exception, being stable with only six electrons. The molecular geometry is described as trigonal planar, with no lone pairs on the central aluminum atom. The AXE notation is used to confirm this geometry.

What is the total number of valence electrons in AlI3?

• 21

• 30

• 24

• 18

Which element is placed at the center of the AlI3 Lewis structure?

• Iodine

• Aluminum

• Hydrogen

• Oxygen

How many valence electrons does aluminum have in the AlI3 structure?

• 8

• 6

• 3

• 5

Which of the following is an exception to the octet rule?

• Oxygen

• Aluminum

• Nitrogen

• Carbon

What is the molecular geometry of AlI3?

• Linear

• Trigonal Planar

• Bent

• Tetrahedral

How many iodine atoms are attached to the central aluminum in AlI3?

• One

• Three

• Four

• Two

What is the steric number of the central aluminum atom in AlI3?

• 2

• 5

• 4

• 3

In AXE notation, what does the 'X' represent in the context of AlI3?

• Lone pairs

• Total valence electrons

• Central atom

• Bonded atoms

What is the AXE notation for AlI3?

• AX4E2

• AX3

• AX2

• AX2E

What is the significance of the 'E' in AXE notation?

• It denotes the total number of atoms.

• It shows the number of bonded atoms.

• It indicates the number of lone pairs.

• It represents the central atom.