Sodium Peroxide Decomposition Analysis

The video tutorial explains how to balance a chemical equation for the decomposition of sodium peroxide into sodium oxide and oxygen gas. It begins by identifying the decomposition reaction and setting up the initial equation. The instructor then demonstrates how to balance the sodium and oxygen atoms by adjusting coefficients, ensuring both sides of the equation have equal numbers of each atom. The process involves placing a coefficient of two in front of sodium peroxide and sodium oxide to achieve balance. The video concludes with a confirmation of the balanced equation.

What type of reaction is demonstrated in the video?

• Single replacement reaction

• Decomposition reaction

• Synthesis reaction

• Double replacement reaction

What are the products formed when sodium peroxide decomposes?

• Sodium chloride and oxygen

• Sodium oxide and hydrogen

• Sodium oxide and oxygen

• Sodium hydroxide and water

How many sodium atoms are present on the reactant side initially?

• Three

• One

• Two

• Four

What is the total number of oxygen atoms on the product side before balancing?

• Four

• Three

• Two

• One

What coefficient is placed in front of sodium peroxide to balance the equation?

• Three

• Four

• Two

• One

After balancing, how many sodium atoms are there on each side of the equation?

• Two

• Five

• Four

• Three

What is the final balanced equation for the decomposition of sodium peroxide?

• 2Na2O2 → Na2O + 2O2

• Na2O2 → Na2O + O2

• 2Na2O2 → 2Na2O + O2

• Na2O2 → 2Na2O + O2