

Tension in Circular Motion
Interactive Video
•
Physics, Mathematics, Science
•
9th - 12th Grade
•
Practice Problem
•
Hard
Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the initial velocity equation mentioned in the video?
V^2 = U^2 - 2gh
V = U - 2gh
V = U + 2gh
V^2 = U^2 + 2gh
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which force acts downward on the object?
Gravitational force
Frictional force
Centrifugal force
Centripetal force
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the formula for centripetal force in this context?
mgh
mu^2/r
mv^2/r
mg cos(theta)
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the two components responsible for tension?
mv^2/r and centrifugal force
mg sin(theta) and mg cos(theta)
mg sin(theta) and mv^2/r
mg cos(theta) and mv^2/r
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the tension equation expressed in terms of velocity and height?
T = mgh + mu^2/r
T = mg cos(theta) + mu^2/r - 2mgh/r
T = mg sin(theta) + mu^2/r
T = mg cos(theta) - mu^2/r + 2mgh/r
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the expression for cos(theta) used in the tension equation?
H + R / r
H - R / r
R - H / r
R + H / r
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final form of the tension equation in terms of theta?
T = m(g cos(theta) + u^2/r - 2g)
T = m(u^2/r - 3gh + rg)
T = m(g cos(theta) + 3g cos(theta) - 2g)
T = m(u^2/r + 2g cos(theta) - 3g)
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