Financial Word Problems and Linear Equations

Financial Word Problems and Linear Equations

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Lucas Foster

FREE Resource

This video tutorial teaches how to determine rent affordability using linear equations. It begins with an introduction to linear relationships and the slope-intercept form. An example of calculating cab fare is used to illustrate common misunderstandings in variable substitution. The tutorial then focuses on a rent problem, defining variables and setting up a linear equation to determine how long one can afford rent. The solution is verified, and the interpretation of the result is discussed, emphasizing the importance of understanding variable meanings.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you earn $500 a month and your rent is $800, how much do you need in your bank account to pay rent for one month?

$300

$500

$1300

$800

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the slope in the equation y = mx + b?

The starting point

The x-intercept

The constant rate of change

The y-intercept

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the cab fare example, what does the variable 'c' represent?

The flat fee

The total charge of the cab fare

The cost per mile

The distance traveled

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the total cab fare is $10.50, which variable should you substitute this value into?

b

c

m

d

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving a word problem involving a linear equation?

Guess the answer

Identify and define known quantities

Write the final answer

Check the solution

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the financial scenario, what does the variable 't' represent?

The number of months that pass

The monthly income

The monthly rent

The total amount in the bank

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What equation represents the scenario where you have $2100, earn $500 monthly, and pay $800 in rent?

0 = 2100 - 500t - 800t

0 = 2100 + 500t + 800t

0 = 2100 - 500t + 800t

0 = 2100 + 500t - 800t

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