Solving a quadratic using the square root method when there are no solutions

The video tutorial explains solving the equation y = X^2 + 3/4 by setting y to zero and isolating X. It highlights that taking the square root of a negative number results in no real solutions, concluding that there are no X intercepts under the real number system.

Explain the process of isolating the variable in the equation y = X^2 + 3/4.

What conclusion can be drawn about the x-intercepts of the equation y = X^2 + 3/4?