Dividing two polynomials using synthetic division

Dividing two polynomials using synthetic division

Assessment

Interactive Video

Mathematics

11th Grade - University

Hard

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The video tutorial explains how to perform synthetic division on a binomial with a coefficient for X. It covers identifying the correct form, determining the value of K by setting the equation to zero, and solving for X. The tutorial demonstrates the steps of synthetic division, including handling fractions and calculating the remainder. Finally, it shows how to derive the final quotient and solution, offering different ways to rewrite the expression.

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5 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the key requirement for a binomial to be used in synthetic division?

It must have a coefficient of 1.

It must be linear.

It must be quadratic.

It must have no constant term.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you determine the value of X for synthetic division in the equation 2X + 3 = 0?

Divide by 3 and multiply by 2.

Subtract 3 and divide by 2.

Multiply both sides by 2.

Add 3 to both sides.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it necessary to include a zero for missing terms in synthetic division?

To make the division easier.

To ensure all terms are accounted for.

To simplify the equation.

To avoid fractions.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying 3 by -3/2 in the synthetic division process?

-9/2

9/2

6

-6

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final form of the quotient in the synthetic division problem discussed?

3X^2 + 17/2X + 51/4

3X^2 - 17/2X - 51/4

3X^2 + 17/2X - 51/4

3X^2 - 17/2X + 51/4