What was Pamela trying to find in the function h(x) = x^3 - 6x^2 + 12x?

Understanding Relative Extrema in Calculus

Interactive Video
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Mathematics
•
9th - 12th Grade
•
Hard

Olivia Brooks
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10 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The point of discontinuity
The absolute maximum
The relative extremum
The inflection point
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the derivative of h(x) = x^3 - 6x^2 + 12x?
3x^2 - 6x + 12
3x^2 - 12x + 12
3x^2 - 12x + 2
3x^2 - 4x + 4
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
At which value of x did Pamela find a critical point?
x = 1
x = 3
x = 2
x = 0
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is a critical point in the context of derivatives?
A point where the function has a maximum value
A point where the derivative is zero or undefined
A point where the function is undefined
A point where the second derivative is zero
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is it incorrect to conclude a relative extremum just because the derivative is zero?
The derivative might not exist
The function might not be continuous
The function might have multiple critical points
The derivative might not change sign
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What must be verified to confirm a relative extremum at a critical point?
The second derivative's value
The function's domain
The derivative's sign change
The function's continuity
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was the result of testing the derivative at x = 1 and x = 3?
The derivative was negative at both points
The derivative was zero at both points
The derivative was positive at both points
The derivative changed sign at both points
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