

Understanding Repeating Decimals and Mathematical Patterns
Interactive Video
•
Mathematics
•
7th - 12th Grade
•
Practice Problem
•
Hard
+5
Standards-aligned
Jackson Turner
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is unique about the decimal representation of 1/998,001?
It includes every four-digit number except 9998.
It includes every two-digit number except 98.
It includes every three-digit number except 998.
It includes every three-digit number except 999.
Tags
CCSS.6.EE.A.1
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What mathematical concept is 998,001 related to?
It is the square of 999.
It is the cube of 999.
It is the square of 99.
It is the cube of 99.
Tags
CCSS.7.NS.A.2D
CCSS.8.NS.A.1
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the number 9999 in the context of repeating decimals?
It is used to generate all three-digit numbers.
It is used to generate all four-digit numbers.
It is used to generate all two-digit numbers.
It is used to generate all five-digit numbers.
Tags
CCSS.7.NS.A.2D
CCSS.8.NS.A.1
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the pattern observed in the decimal representation of 1/81?
It includes all two-digit numbers except 18.
It includes all one-digit numbers except 8.
It includes all two-digit numbers except 81.
It includes all one-digit numbers except 9.
Tags
CCSS.4.NF.C.6
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of 1/9 squared in decimal form?
0.01234567
0.012345679
0.012345678
0.01234568
Tags
CCSS.7.NS.A.2D
CCSS.8.NS.A.1
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can any repeating decimal be constructed?
By dividing a sequence of digits by a series of 9s.
By multiplying a sequence of digits by a series of 8s.
By dividing a sequence of digits by a series of 8s.
By multiplying a sequence of digits by a series of 9s.
Tags
CCSS.HSA.SSE.B.4
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What formula simplifies complex repeating decimals?
1 + 2x + 3x^2 + 4x^3 = 1/(1+x)^2
1 + 2x + 3x^2 + 4x^3 = 1/(1-x)^3
1 + 2x + 3x^2 + 4x^3 = 1/(1-x)^2
1 + 2x + 3x^2 + 4x^3 = 1/(1-x)
Tags
CCSS.5.NBT.A.2
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