Police Chase Time and Speed Problems

The video tutorial explains a problem involving a bank robber and a police officer. The robber runs at 8 mph, and the officer starts 15 minutes later at 12 mph. The tutorial uses the distance equals rate times time formula to set up and solve an equation to find out how long it takes for the officer to catch the robber. The solution involves converting time units and solving a linear equation, resulting in the officer catching the robber in half an hour.

What is the speed of the robber in the problem?

• 12 mph

• 10 mph

• 8 mph

• 6 mph

Tags

CCSS.8.EE.B.5

How much time does the police officer wait before starting the chase?

• 10 minutes

• 15 minutes

• 20 minutes

• 25 minutes

Tags

CCSS.8.EE.C.7B

What formula is used to solve the problem?

• Rate = Distance x Time

• Speed = Distance / Time

• Distance = Rate x Time

• Time = Distance / Speed

Tags

CCSS.8.EE.C.7B

What is the speed of the police officer on the bicycle?

• 16 mph

• 12 mph

• 14 mph

• 10 mph

Tags

CCSS.8.EE.B.5

How is the 15-minute head start converted for the equation?

• 1/4 hour

• 1/5 hour

• 1/3 hour

• 1/2 hour

What is the equation set up to find the time when the officer catches the robber?

• 8(T + 1/4) = 12T

• 8T = 12(T + 1/4)

• 8(T - 1/4) = 12T

• 8T = 12T

Tags

CCSS.HSA.REI.A.1

What is the first step in solving the equation?

• Subtract 8T from both sides

• Add 8T to both sides

• Divide both sides by 4

• Multiply both sides by 4

Tags

CCSS.6.EE.B.7

What is the value of T when the equation is solved?

• 1 hour

• 3/4 hour

• 1/2 hour

• 1/4 hour

Tags

CCSS.8.EE.C.7B

How long does it take for the police officer to catch the robber in minutes?

• 30 minutes

• 25 minutes

• 20 minutes

• 15 minutes

Tags

CCSS.5.MD.B.2

What is the final answer to the problem in terms of hours?

• 1/4 hour

• 1/2 hour

• 3/4 hour

• 1 hour

Tags

CCSS.5.MD.B.2