Distributive Property and Simplification

The video tutorial explains how to use the distributive property to simplify algebraic expressions. It covers two examples, demonstrating how to distribute and simplify terms by identifying and canceling common factors. The tutorial emphasizes writing terms as fractions to facilitate simplification and provides a clear, step-by-step approach to solving each expression. The video concludes with a summary of the simplification process.

What is the first step in using the distributive property for the expression 4/7 times (21y + 14)?

• Divide 21y by 14

• Multiply 4/7 by each term inside the parentheses

• Add 21y and 14

• Subtract 14 from 21y

Tags

CCSS.7.EE.A.2

CCSS.HSA.SSE.A.2

How do you express 21y as a fraction?

• 21y/1

• 7/21y

• 21y/7

• 1/21y

What is the simplified form of 4/7 times 21y?

• 4y

• 3y

• 21y

• 12y

What common factor is used to simplify 4/7 times 14?

• Seven

• Fourteen

• Four

• Two

Tags

CCSS.6.EE.A.3

What is the final simplified expression of 4/7 times (21y + 14)?

• 12y + 8

• 14y + 8

• 8y + 12

• 12y + 14

Tags

CCSS.7.EE.A.1

What is the first step in simplifying 35 times (5/7x + 2/5)?

• Divide 35 by 5/7x

• Add 5/7x and 2/5

• Multiply 35 by each term inside the parentheses

• Subtract 2/5 from 5/7x

Tags

CCSS.3.NF.A.3C

How do you express 35 as a fraction?

• 35/7

• 1/35

• 7/35

• 35/1

Tags

CCSS.7.EE.A.1

What is the simplified form of 35 times 5/7x?

• 25x

• 5x

• 35x

• 7x

What common factor is used to simplify 35 times 2/5?

• Two

• Five

• Ten

• Seven

Tags

CCSS.6.EE.A.3

What is the final simplified expression of 35 times (5/7x + 2/5)?

• 10x + 25

• 25x + 14

• 25x + 10

• 14x + 25

Tags

CCSS.6.EE.A.3