Solving Two-Step Equations with the Distributive Property

What is the first step in solving equations with the distributive property?

• Change any subtraction to add the opposite

• Add 10 to both sides

• Divide both sides by the outer term

• Multiply the outer term by each term inside the parentheses

Tags

CCSS.8.EE.C.7B

After distributing and simplifying, what is the next step?

• Subtract 10 from both sides

• Add 10 to both sides

• Divide both sides by the coefficient of x

• Multiply both sides by 2

Tags

CCSS.7.EE.B.4A

How do you check if the solution to an equation is correct?

• Multiply the solution by 2

• Divide the solution by 2

• Add 5 to the solution

• Substitute the solution back into the original equation

Tags

CCSS.6.EE.B.5

What alternative method can be used to solve equations involving the distributive property?

• Adding both sides by the same number

• Multiplying both sides by the outer term

• Dividing both sides by the outer term

• Subtracting both sides by the same number

Tags

CCSS.8.EE.C.7B

What is the result of dividing negative 16 by 2 in the alternative method?

• -16

• 16

• -8

• 8

Tags

CCSS.7.NS.A.2A

CCSS.7.NS.A.2B

In the final example, what is the first step using the distributive property?

• Divide both sides by 2

• Subtract 6 from both sides

• Add 4 to both sides

• Multiply 2 by each term inside the parentheses

Tags

CCSS.HSA.REI.A.1

How do you simplify the expression after applying the distributive property in the final example?

• Combine like terms

• Divide by 2

• Multiply by -10

• Subtract 6 from both sides

Tags

CCSS.6.EE.A.3

What is the final step to solve the equation in the last example?

• Divide both sides by -10

• Multiply both sides by -10

• Subtract 6 from both sides

• Add 6 to both sides

Tags

CCSS.7.EE.B.4A

What is the solution to the equation in the last example?

• 1.4

• 14

• -14

• -1.4

Tags

CCSS.7.EE.B.4A

How do you verify the solution in the last example?

• Substitute the solution back into the original equation

• Divide the solution by 2

• Multiply the solution by 2

• Add 4 to the solution

Tags

CCSS.7.EE.B.4A