

Solving Transversal Equations for X
Interactive Video
•
Mathematics
•
6th - 10th Grade
•
Practice Problem
•
Hard
+1
Standards-aligned
Emma Peterson
FREE Resource
Standards-aligned
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of color coding angles in a transversal?
To differentiate between acute and obtuse angles
To indicate which angles are supplementary
To make the diagram more visually appealing
To identify congruent angles easily
Tags
CCSS.8.G.A.5
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If one angle in a transversal is 40 degrees, what is the measure of its vertical angle?
90 degrees
40 degrees
180 degrees
140 degrees
Tags
CCSS.6.EE.B.7
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How can you solve for x if 5x equals 140?
Add 5 to both sides
Divide both sides by 5
Subtract 140 from both sides
Multiply both sides by 5
Tags
CCSS.8.G.A.5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of solving the equation 40 + 5x = 180 for x?
x = 140
x = 35
x = 18
x = 28
Tags
CCSS.HSA.REI.A.1
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When solving for y using the equation 3y - 1 + 40 = 180, what is the first step?
Multiply both sides by 3
Subtract 40 from both sides
Add 1 to both sides
Divide both sides by 3
Tags
CCSS.6.EE.B.7
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the value of y when solving the equation 3y = 141?
y = 3
y = 142
y = 47
y = 141
Tags
CCSS.7.EE.B.4A
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you find the value of x when given the equation 6x + 7 = 115?
Add 7 to both sides
Subtract 7 from both sides
Multiply both sides by 6
Divide both sides by 6
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