Mastering One Step Equations

This video tutorial introduces solving one-step equations, focusing on the basic types. It explains what a solution to an equation is and demonstrates the addition and multiplication principles used to solve these equations. The video provides examples of solving equations using both principles, emphasizing the goal of isolating the variable. It concludes with examples involving fractions and highlights the importance of maintaining balance by performing the same operation on both sides of the equation.

What is the purpose of solving an equation?

• To simplify the equation without solving

• To prove that both sides are unequal

• To isolate the variable on one side of the equation

• To find the highest value of the variable

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CCSS.7.EE.B.4A

What does the addition principle state about equations?

• Subtracting the same value from both sides invalidates the equation

• Adding the same value to both sides keeps the equation true

• Adding the same value to both sides changes the equation's outcome

• Adding different values to each side keeps the equation balanced

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CCSS.HSA.REI.A.1

How can you solve the equation X + 4 = 11 using the addition principle?

• Add 4 to both sides

• Subtract 4 from both sides

• Divide both sides by 4

• Multiply both sides by 4

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CCSS.6.EE.B.7

What is the solution to the equation X - 8 = 21?

• X = 13

• X = 29

• X = 17

• X = 12

Tags

CCSS.6.EE.B.7

In the context of one-step equations, what does isolating the variable involve?

• Adding a constant to both sides

• Removing all variables except one

• Getting the variable on one side of the equation by itself

• Multiplying the variable by zero

Tags

CCSS.6.EE.B.7

What operation would you use to solve the equation 5X = 75?

• Division

• Multiplication

• Subtraction

• Addition

Tags

CCSS.HSA.REI.A.1

How do you solve an equation where a variable is divided by a number, such as X/4 = 8?

• Add 4 to both sides

• Subtract 4 from both sides

• Multiply both sides by 4

• Divide both sides by 4

Tags

CCSS.6.EE.B.7

What is the result of solving the equation 2/3Y = 16 using the multiplication principle?

• Y = 24

• Y = 12

• Y = 8

• Y = 32

Tags

CCSS.6.EE.B.7

When solving the equation X divided by -3 = 9, what is the correct operation to isolate X?

• Divide both sides by -3

• Multiply both sides by -3

• Add 3 to both sides

• Subtract 3 from both sides

Tags

CCSS.6.EE.B.7

What principle is applied when dividing both sides of an equation by the same number?

• Subtraction principle

• Multiplication principle

• Addition principle

• Division principle

Tags

CCSS.HSA.REI.A.1