
Finding the Equation of a Circle with Given Radius and Center

Interactive Video
•
Mathematics
•
8th - 12th Grade
•
Hard
Standards-aligned

Lucas Foster
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the standard form of a circle's equation?
x^2 + y^2 = r^2
(x - h)^2 + (y - k)^2 = r^2
(x + h)^2 + (y + k)^2 = r^2
x^2 + y^2 + r^2 = 0
Tags
CCSS.HSG.GPE.A.1
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does 'r' represent in the standard form of a circle's equation?
The area of the circle
The radius of the circle
The circumference of the circle
The diameter of the circle
Tags
CCSS.HSG.GPE.A.1
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If a circle's equation is (x - h)^2 + (y - k)^2 = r^2, what do 'h' and 'k' represent?
The circle's center coordinates
The coordinates of any point on the circle
The slope of the tangent to the circle at any point
The diameter's endpoints
Tags
CCSS.HSG.GPE.A.1
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the correct way to express a circle's radius in its equation?
As the diameter divided by 2
As the value 'r' squared on the right side of the equation
As the square root of the right side of the equation
As the square of the right side of the equation
Tags
CCSS.HSG.GPE.A.1
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Given a circle with center (15, 14) and radius 7, what is its equation?
(x - 15)^2 + (y - 14)^2 = 49
(x + 15)^2 + (y + 14)^2 = 49
(x - 7)^2 + (y - 7)^2 = 196
(x + 7)^2 + (y + 7)^2 = 49
Tags
CCSS.HSG.GPE.A.1
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How is the equation of a circle derived when given its center and radius?
By calculating the distance between the center and any point on the circle
By drawing the circle and measuring its diameter
By substituting the center's coordinates and radius into the standard form
By squaring the radius and adding it to the center's coordinates
Tags
CCSS.HSG.GPE.A.1
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For a circle centered at (0, -6) with a radius of 3, what is the correct equation?
(x + 3)^2 + (y - 6)^2 = 9
(x - 3)^2 + (y + 6)^2 = 0
x^2 + (y - 6)^2 = 9
x^2 + (y + 6)^2 = 9
Tags
CCSS.HSG.GPE.A.1
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