Common Ion Effect and Solubility

Professor Dave introduces the common ion effect, an application of Le Chatelier's principle, which helps predict and control precipitation. He explains how adding a common ion shifts equilibrium, using silver iodide and cadmium sulfide as examples. The video demonstrates how the presence of a common ion reduces solubility, promoting precipitation.

What is the main topic discussed by Professor Dave in this tutorial?

• Le Chatelier’s principle

• The common ion effect

• Chemical kinetics

• Thermodynamics

Which principle is the common ion effect an application of?

• Avogadro’s law

• Charles’s law

• Le Chatelier’s principle

• Boyle’s law

What happens to an equilibrium when an additional amount of one of the components is added?

• The equilibrium shifts towards the other side

• The equilibrium is destroyed

• The equilibrium shifts towards the added component

• The equilibrium remains unchanged

In the example of silver iodide equilibrium, which ion is common between silver iodide and potassium iodide?

• Iodide ion

• Sulfide ion

• Potassium ion

• Silver ion

What effect does adding potassium iodide have on the equilibrium of silver iodide?

• It shifts the equilibrium to the right

• It shifts the equilibrium to the left

• It has no effect on the equilibrium

• It dissolves the silver iodide

What is the Ksp value of cadmium sulfide?

• 1 x 10^-20

• 1 x 10^-10

• 1 x 10^-38

• 1 x 10^-28

In the cadmium sulfide example, what is the initial concentration of cadmium ion from cadmium bromide?

• 1 M

• 0.01 M

• 0.1 M

• 0.001 M

Why can the additional concentration of cadmium from cadmium sulfide be considered negligible?

• Because cadmium sulfide does not dissolve

• Because the initial cadmium ion concentration is very high

• Because the Ksp value is very large

• Because the equilibrium concentration of cadmium is zero

What is the molar solubility of cadmium sulfide in a 0.01 M cadmium bromide solution?

• 1.0 x 10^-28

• 1.0 x 10^-26

• 1.0 x 10^-20

• 1.0 x 10^-10

How does the presence of cadmium ions in solution affect the molar solubility of cadmium sulfide?

• It has no effect on the molar solubility

• It dissolves the cadmium sulfide completely

• It decreases the molar solubility

• It increases the molar solubility