Solving Equations and Proportions

This video tutorial explains how to find proportional segments in parallel lines cut by two transversals. It demonstrates setting up and solving a proportion using algebraic methods. The example problem involves three parallel lines and two transversals, where the segments formed are proportional. The tutorial guides through setting up the proportion and solving for the unknown variable using cross-multiplication and simplification techniques.

What happens when three or more parallel lines are cut by two transversals?

• The line segments formed are equal.

• The line segments formed are congruent.

• The line segments formed are proportional.

• The line segments formed are perpendicular.

Given that lines L, M, and N are parallel, what can be said about the segments formed by the transversals?

• They are proportional.

• They are equal in length.

• They are perpendicular.

• They are congruent.

How is the proportion set up for the given problem?

• X + 1 is to 13 as X + 4 is to 19.

• X + 1 is to 13 as X + 4 is to 13.

• X + 1 is to X + 4 as 13 is to 19.

• X + 1 is to 19 as X + 4 is to 13.

What is the first step in solving the proportion using cross-multiplication?

• Multiply the segments across.

• Add the segments together.

• Subtract the segments.

• Divide the segments.

What is the result of distributing 19 in the equation 19(X + 1)?

• 19X + 19

• 19X + 1

• 19X + 4

• 19X + 13

What do you get when you subtract 13X from both sides of the equation 19X + 19 = 13X + 52?

• 6X + 19 = 13

• 6X + 19 = 19

• 6X + 19 = 33

• 6X + 19 = 52

After subtracting 19 from both sides of the equation 6X + 19 = 52, what is the resulting equation?

• 6X = 52

• 6X = 33

• 6X = 13

• 6X = 19

What is the final value of X after simplifying 33/6?

• 11/2

• 11/6

• 11/4

• 11/3