Solving One Step Equations with Multiplication and Division

The video tutorial explains how to solve linear equations by isolating variables. It covers four examples: solving 6m = -30, 8 = -2z, w/6 = 5, and -2 = x/-4. Each example demonstrates the process of using inverse operations to isolate the variable and verify the solution. The tutorial emphasizes understanding the relationship between multiplication and division in solving equations.

What is the first step in solving an equation?

• Multiply both sides by zero

• Isolate the variable

• Subtract a constant from both sides

• Add a constant to both sides

Tags

CCSS.7.EE.B.4A

In the equation 6m = -30, what operation is used to isolate m?

• Subtraction

• Division

• Addition

• Multiplication

Tags

CCSS.HSA.REI.A.1

What is the value of m in the equation 6m = -30?

• -6

• 5

• 6

• -5

Tags

CCSS.6.EE.B.7

How do you verify the solution m = -5 for the equation 6m = -30?

• Subtract 5 from both sides

• Multiply both sides by 5

• Add 5 to both sides

• Substitute -5 for m and check if both sides are equal

Tags

CCSS.6.EE.B.5

In the equation 8 = -2z, what operation is used to isolate z?

• Addition

• Division

• Subtraction

• Multiplication

Tags

CCSS.6.EE.B.7

What is the value of z in the equation 8 = -2z?

• 4

• -8

• -4

• 8

Tags

CCSS.6.EE.B.7

In the equation w/6 = 5, what operation is used to isolate w?

• Subtraction

• Multiplication

• Division

• Addition

Tags

CCSS.HSA.REI.A.1

What is the value of w in the equation w/6 = 5?

• 6

• 30

• 25

• 5

Tags

CCSS.6.EE.B.7

In the equation -2 = x/-4, what operation is used to isolate x?

• Addition

• Subtraction

• Multiplication

• Division

Tags

CCSS.6.EE.B.7

What is the value of x in the equation -2 = x/-4?

• 4

• -8

• 8

• -4

Tags

CCSS.6.EE.B.7