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Lingkaran dan Polinimial

Authored by Ram Tome

Mathematics

11th Grade

Lingkaran dan Polinimial
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20 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

The center and radius of the circle with the equation 𝑥 2 + 𝑦2 + 4𝑥 − 6𝑦 − 12 = 0 are ….

(-2, 3) and 5

(-2, 3) and 6

(-2, 3) and 7

(2, -3) and 5

(2, -3) and 6

2.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

The circle 𝑥2 + 𝑦2+ 4𝑥 + 2𝑏𝑦 − 12 = 0 passes through the point (1, 7). The center of the circle is ….

(2, 3)

(-2, -3)

(-2, 3)

(2, -3)

(3, 2)

3.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

The equation of a circle with center (−1, 3) that is tangent to the Y-axis is ....

𝑥 2 + 𝑦2 + 2𝑥 − 6𝑦 + 1 = 0

𝑥2 + 𝑦2 − 2𝑥 + 6𝑦 + 1 = 0

𝑥 2+ 𝑦2 + 2𝑥 − 6𝑦 + 9 = 0

𝑥 2+ 𝑦2 + 𝑥 − 3𝑦 + 9 = 0

𝑥 2+ 𝑦2 + 𝑥 − 3𝑦 + 1 = 0

4.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

Given the circle 2𝑥2 + 2𝑦2 − 4𝑥 + 3𝑝𝑦 − 30 = 0 that passes through the point (−2, 1). The equation of the circle that is concentric but has a radius twice that of the given circle is ….

2𝑥2 + 2𝑦2 − 4𝑥 + 12𝑦 − 90 = 0

2𝑥2 + 2𝑦2 − 4𝑥 + 12𝑦 + 90 = 0

𝑥2 + 𝑦2 − 2𝑥 − 6𝑦 − 90 = 0

𝑥2 + 𝑦2 − 2𝑥 + 6𝑦 − 90 = 0

𝑥2 + 𝑦2 − 𝑥 + 3𝑦 − 90 = 0

5.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

The equation of a circle with center P(3, 1) that is tangent to the line 3x + 4y + 7 = 0 is ….

𝑥2 + 𝑦2 − 6𝑥 − 2𝑦 + 6 = 0

𝑥2 + 𝑦2 − 6𝑥 + 2𝑦 − 6 = 0

𝑥2 + 𝑦2 + 6𝑥 − 2𝑦 − 6 = 0

𝑥2 + 𝑦2 + 6𝑥 + 2𝑦 − 6 = 0

𝑥2 + 𝑦2 − 6𝑥 − 2𝑦 − 6 = 0

6.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

The equation of a circle whose center is located on the line 2𝑥 – 4𝑦 – 4 = 0 and is tangent to the negative X-axis and the negative Y-axis is ….

𝑥2 + 𝑦2 + 4𝑥 + 4𝑦 + 4 = 0

𝑥2 + 𝑦2 + 4𝑥 + 4𝑦 + 8 = 0

𝑥2 + 𝑦2 + 2𝑥 + 2𝑦 + 4 = 0

𝑥2 + 𝑦2 + 2𝑥 + 2𝑦 + 2 = 0

𝑥2 + 𝑦2 + 𝑥 + 𝑦 + 2 = 0

7.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

Given a circle with the equation 𝑥2 + 𝑦2 + m𝑥 + 4 𝑦 + 3 = 0 and the point P(4, 1) lies on the circle. The points A and B, which are both located inside the circle, are ….

A(-2, 1) and B(-4, 4)

A(2, -1) and B(4, -4)

A(2, -1) and B(2, -2)

A(1, -1) and B(2, -2)

A(1, -1) and B(4, -4)

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