CUA Topic 2 Assessment

Part A

The table shows the number of people at the last three baseball games. Estimate the total attendance by rounding each number in the table to the nearest thousand and finding the sum.

• 6,000 + 2, 000 + 3,000= 11,000

• 5,000 + 2,000+ 3,000= 10,000

• 6,000 + 2,000 + 4,000= 12,000

• 5,000 + 2,000+ 2,000= 9,000

Tags

CCSS.4.OA.A.3

Part B.

Write and solve an equation to find the total attendance.

• 5,753 + 2,250 + 3,160 = 11,163

• 5,753 + 2,250 + 3,160 = 10,163

• 5,753 + 2,250 + 3,160 = 12,163

• 5,753 + 2,250 + 3,160 = 9,163

Find 3,000 - 2,450.

• 550

• 450

• 600

• 500

Tags

CCSS.4.NBT.B.4

Enter the missing digits to complete the subtraction.
1 0, 8 8 1
- 4, 9 6 0
_______
​

​

• 5,921

• 4, 921

• 2,921

• 6, 921

Find the difference. 9,601 - 939 =

• 9,338

• 1,932

• 9,372

• 8,662

Tags

CCSS.4.NBT.B.4

Complete the equation to make it true.

Write your answer in the box.

(4,200 + 75) + 5 = ( ​ (a)   ) + (75 + 5)

• 4,200
• 4,280
• 4,100

Tags

CCSS.4.NBT.B.4

Find the difference. Then use addition to check your work.

• 9,487

• 8,932

• 10,123

• 9,200

Tags

CCSS.4.NBT.B.4

Which of the following statements is true? Select all that apply.

• 61,640 + 1,111 = 62,751

• 62,561 − 17,638 = 80,199

• 15,020 + 8,604 = 23,660

• 12,314 − 9,103 = 3,211

• 22,222 − 11,111 = 11,111

Find the sum.

• 15,328

• 14,920

• 16,002

• 15,100

Tags

CCSS.4.NBT.B.4

DuJuan used addition properties to rewrite the equation below. Select all the equations DuJuan might have written.

• 3,010 + 1,505 + 2,370 = n

• 3,010 + 1,505 = n

• 3,000 + 2,300 + 1,500 = n

• (2,370 + 3,010) + 1,505 = n

• (3,000 + 2,300 + 1,500) + (10 + 70 + 5) = n

Tags

CCSS.4.NBT.B.4