dunglamtraitimanhdau

If the particle through a potential difference V, the change in the electric potential energy is

(24-4)

• ΔU = q / ΔV

• ΔU = q ΔV

• ΔU = ΔV / q

• ΔU = -q ΔV

The plane of the sheet and has magnitude:

(sheet of charge: 23-13)

• E = σ / ε0

• E = σ / 2ε0

• E = σ / 3ε0

• E = σ / 4ε0

• 1 and 2 leftward, 3 rightward

  2 > 1 = 3, 3

  accelerate leftward

• 1, 2 and 3 rightward

  1 > 2 = 3, 2

  accelerate rightward

• 1 and 3 rightward, 2 leftward

  2 > 1 = 3, 2

  accelerate rightward

• 2 and 3 rightward, 1 leftward

  3 > 1 = 2, 3

  accelerate leftward

• VA > VC (0) > VB

• VB > VA > VC

• VB = VA > VC

• VC > VA = VB

• -x

• -y

• -z

• +x

• +y

Potential Due to a Continuous Charge Distribution is

(24 - 32)

• V = ( 1 / 4πε0) ∫ dqr

• V = ( 1 / 4πε0) ∫ -dqr

• V = ( 1 / 4πε0) ∫ dq / r

• V = ( 1 / 4πε0) ∫ -dq / r

• (a) +EA

  (b) -EA

  (c) 0

  (d) 0

• (a) -EA

  (b) +EA

  (c) 0

  (d) 0

• (a) 0

  (b) 0

  (c) +EA

  (d) -EA

• (a) +EA

  (b) 0

  (c) 0

  (d) -EA

• clockwise

• counterclockwise

• electron

• proton

The magnitude of the electric field set up by the dipole at a distant point on the dipole axis (which runs through both charges) is

( 22 - 9 )

• E = 1 / 2πε0 . p / z^3

• E = 1 / 4πε0 . p / z^2

• E = 1 / 2πε0 . p / z^2

• E = 1 / 4πε0 . p / z^3

• (a) +y - axis

  (b) +x - axis

  (c) -y - axis

• (a) +y - axis

  (b) -x - axis

  (c) -y - axis

• (a) -y - axis

  (b) +x - axis

  (c) +y - axis

• (a) -y - axis

  (b) -x - axis

  (c) +y - axis