TYS 5105 C11 (D.C. Circuits)

TYS 5105 C11 (D.C. Circuits)

10th Grade

12 Qs

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TYS 5105 C11 (D.C. Circuits)

TYS 5105 C11 (D.C. Circuits)

Assessment

Quiz

Physics

10th Grade

Easy

Created by

Han Kuang

Used 1+ times

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12 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which circuit is used to vary the brightness of a lamp?

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Answer explanation

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2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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In the circuit shown, the switches S1 and S2 may be open (off) or closed (on).

Which row shows the voltmeter reading when the switches are in the positions given in the table?

S1: open,

S2: open,

voltmeter reading/V:

12

S1: closed,

S2: closed,

voltmeter reading/V:

12

S1: open,

S2: closed,

voltmeter reading/V:

0

S1: closed,

S2: open,

voltmeter reading/V:

12

Answer explanation

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3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Three 240V lamps, of different power ratings, are connected as shown. In which circuit are all three lamps lit at their normal brightness?

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Answer explanation

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4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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Four lamps and four switches are connected to a power supply as shown in the circuit diagram. When all the switches are closed, all the lamps are lit. When one of the switches is then opened, only one lamp goes out. Which switch is opened?

A

B

C

D

Answer explanation

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5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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In the circuit shown, the reading on ammeter 1 is 2A.

What is the reading on ammeter 2?

0 A

1 A

2 A

4 A

Answer explanation

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6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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A circuit containing three resistors with resistances, X, Y and Z, is set up.

Which formula can be used to find the total effective resistance, Rtotal, of the three resistors?

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Answer explanation

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7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

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The circuit shown is set up.

Which statement is correct?

voltage across lamp 2 is higher than the voltage across lamp 1

voltage across lamp 1 is higher than the voltage across lamp 2

voltage of battery = voltage across lamp 1 + voltage across lamp 2

voltage of battery = voltage across lamp 1 = voltage across lamp 2

Answer explanation

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