Glycolysis Process Quiz

What is the first step in the process of glycolysis?

• Priming

• Cleavage

• Phosphorylation

• Oxidation

Answer explanation

The first step in glycolysis is phosphorylation, where glucose is converted to glucose-6-phosphate. This step is crucial for trapping glucose in the cell and preparing it for further breakdown.

Tags

NGSS.HS-LS1-7

Which step in glycolysis involves the splitting of a molecule?

• Priming

• Cleavage

• Oxidation

• Dephosphorylation

Answer explanation

The cleavage step in glycolysis is where the 6-carbon sugar is split into two 3-carbon molecules, specifically glyceraldehyde-3-phosphate (G3P). This is a key step in the glycolytic pathway.

Tags

NGSS.HS-LS1-7

During which step of glycolysis does the removal of a phosphate group occur?

• Phosphorylation

• Priming

• Dephosphorylation

• Oxidation

Answer explanation

Dephosphorylation is the step in glycolysis where a phosphate group is removed from a molecule, specifically during the conversion of 1,3-bisphosphoglycerate to 3-phosphoglycerate, releasing energy.

Which step in glycolysis is crucial for the conversion of glucose into pyruvate?

• Phosphorylation

• Cleavage

• Oxidation

• End Result

Answer explanation

The 'End Result' of glycolysis is the conversion of glucose into pyruvate, which is the final product of the pathway. While phosphorylation, cleavage, and oxidation are important steps, they lead to this crucial end result.

What is the role of hexokinase in the glycolysis process?

• It converts glucose into pyruvate.

• It transfers an inorganic phosphate group from ATP to glucose.

• It splits fructose 1,6-diphosphate into two molecules.

• It oxidizes PGAL by removing hydrogen atoms.

Answer explanation

Hexokinase plays a crucial role in glycolysis by transferring an inorganic phosphate group from ATP to glucose, converting it into glucose-6-phosphate, which is the first step in the glycolytic pathway.

What happens to fructose 1,6-diphosphate during the cleavage phase of glycolysis?

• It is oxidized by removing hydrogen atoms.

• It is split into two three-carbon molecules.

• It is converted into glucose 6-phosphate.

• It is phosphorylated to form ATP.

Answer explanation

During the cleavage phase of glycolysis, fructose 1,6-diphosphate is split into two three-carbon molecules, specifically glyceraldehyde 3-phosphate and dihydroxyacetone phosphate, which are crucial for further energy production.

Which molecule is oxidized during the oxidation phase of glycolysis?

• Glucose

• Fructose 6-phosphate

• PGAL (phosphoglyceraldehyde)

• Pyruvate

Answer explanation

During the oxidation phase of glycolysis, PGAL (phosphoglyceraldehyde) is oxidized to form 1,3-bisphosphoglycerate, making it the correct answer. Glucose and fructose 6-phosphate are not oxidized in this phase.

What is the main outcome of the dephosphorylation phase in glycolysis?

• Formation of NADH

• Production of ATP

• Conversion of glucose to fructose

• Splitting of PGAL

Answer explanation

The main outcome of the dephosphorylation phase in glycolysis is the production of ATP. This phase involves substrate-level phosphorylation, where energy-rich ATP is generated from ADP.

What is the end product of glycolysis?

• Glucose

• Fructose 6-phosphate

• 2 Pyruvate + 2 NADH + 2 ATP + 2 H+

• 2 PGAL

Answer explanation

The end product of glycolysis is 2 pyruvate, along with 2 NADH, 2 ATP, and 2 H+. This process breaks down glucose to extract energy, making the correct answer 2 Pyruvate + 2 NADH + 2 ATP + 2 H+.

Tags

NGSS.HS-LS2-5

What prevents sugar from leaving the cell during glycolysis?

• Conversion to pyruvate

• Phosphorylation of glucose

• Oxidation of PGAL

• Cleavage of fructose 1,6-diphosphate

Answer explanation

Phosphorylation of glucose traps it in the cell by converting it to glucose-6-phosphate, preventing its exit. This is a key regulatory step in glycolysis, ensuring that glucose is utilized for energy production.