Mathematical Induction Concepts

Mathematical Induction Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains a standard proof by mathematical induction. It begins with verifying the base case for n=1, showing that the sum of 1/k^2 from 1 to n is less than or equal to 2 - 1/n. The inductive hypothesis assumes the statement is true for n=C, and the inductive step proves it for n=C+1. The proof concludes by demonstrating that the statement holds for all positive integers.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in a mathematical induction proof?

Test the base case

Prove the statement for n=k+1

Assume the statement is true for n=k

Simplify the inequality

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the base case, what is the value of the right-hand side when n=1?

2

1

0

3

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of the inductive hypothesis in a proof by induction?

To simplify the inequality

To conclude the proof

To assume the statement is true for a specific integer

To prove the statement for n=1

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is it important to choose a different letter than 'k' for the inductive hypothesis?

To avoid confusion with the variable in the sum

To make the proof more complex

To simplify the calculations

To ensure the proof is valid

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after assuming the statement is true for n=C?

Prove the statement for n=C+1

Simplify the inequality

Conclude the proof

Test the base case

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you modify the left-hand side to include the term for C+1?

Subtract the term for C+1

Divide by C+1

Add the term for C+1

Multiply by C+1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of finding a common denominator in the inequality?

To conclude the proof

To prove the base case

To simplify the inequality

To make the inequality more complex

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