Gram to Gram Stoichiometry

Calculate the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid according to the balanced equation below. 2Al + 6HCl → 2 AlCl3 + 3 H2

• 1.5 g

• 2.0 g

• 3.0 g

• 6.0 g

• 12 g

Tags

NGSS.HS-PS1-7

2Na + 2H₂O → 2NaOH+ H₂
How many grams of hydrogen are produced if 120 g of Na are available?

• 5.2 g

• 2.6 g

• 690 g

• 45 g

Tags

NGSS.HS-PS1-7

B₂H₆ + 3O₂ -->2 HBO₂ + 2 H₂O
 What mass of O₂ will be needed to burn 36.1 g of B₂H₆?

• 13.8 g O₂

• 3.86 mol of O₂

• 124 g O₂

Tags

NGSS.HS-PS1-7

2Al + 3H₂SO₄ -> Al₂(SO₄)₃ + 3H₂
How many grams of aluminum sulfate would be formed if 250g H₂SO₄ completely reacted with aluminum?

• 0.85 g

• 290 g

• 450 g

• 870 g

Tags

NGSS.HS-PS1-7

SiO₂ + 3C → SiC + 2CO
I need to add 8 moles of Carbon to the reaction. How many grams of Carbon should I weigh?

• _{96 g}

• 0.67 g

• 2.67 g

• 48 g

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Tags

NGSS.HS-PS1-2

NGSS.HS-PS1-7

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Tags

NGSS.HS-PS1-7

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Tags

NGSS.HS-PS1-7

• 6.02 x10²³ molecules

• 1.2 x 10²⁴ molecules

• 3.01 x 10²³ molecules

• 1.8 x 10²⁴ molecules

• none of the above

Answer explanation

1 mole of H₂ produces 1 mole of H₂SO₄, and 1 mole = 6.02 x10²³ molecules

Tags

NGSS.HS-PS1-7

Calculate the mass of water produced when 44 g of propane (C3H8) is burned in excess oxygen according to the balanced equation: @@ ext{C}_3 ext{H}_8 + 5 ext{O}_2 ightarrow 3 ext{CO}_2 + 4 ext{H}_2 ext{O}@@

• A) 36 g

• B) 44 g

• C) 72 g

• D) 88 g