
AP Chemistry Unit 9
Authored by Lisa Thompson
Science
12th Grade
NGSS covered

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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Two different electrolytic cells are constructed to electroplate two identical objects based on the half reactions given in the table above. Which of the following mathematical relationships can be used to determine how much more current is needed to electroplate an object with Au than to electroplate it with Ag?
The difference in standard reduction potential of Au3+ and Ag+
is 0.70V.
Three times more electrons are needed to reduce Au3+(aq)
to Au(s) than are needed to reduce Ag+(aq) to Ag(s).
ΔG° is more negative for the reduction of Au3+(aq)
to Au(s) than for the reduction of Ag+(aq) to Ag(s).
Tags
NGSS.HS-PS2-5
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The diagrams above illustrate the equipment used to electroplate four identical objects with silver or zinc. The table provides the conditions used. Which of the following provides the basis for the identification of the object that requires the highest current, I, to complete the electroplating?
Object 1, based on the molar mass of Ag and the time of operation.
Object 2, based on the molar mass of Ag and the time of operation.
Object 3, based on the coulombs of charge needed and the time of operation.
Object 4, based on the coulombs of charge needed and the time of operation.
Tags
NGSS.HS-PS3-1
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Under standard conditions, a Ni-Cd galvanic cell generates a potential of +0.15V using the chemical reaction represented above. Which of the following best explains how [Ni2+]>1M affects the cell potential if this is the only change made to the operation of the galvanic cell?
The ratio [Cd2+]/[Ni2+] is smaller if [Ni2+]>1M, resulting in Q<1
Q<1 and Ecell>E°cell.
The ratio [Cd2+]/[Ni2+] is smaller if [Ni2+]>1M resulting in Q>1
and Ecell>E°cell.
The ratio [Ni2+]/[Cd2+] is larger if [Ni2+]>1M, resulting in Q>1 and Ecell
The ratio [Ni2+]/[Cd2+] is larger if [Ni2+]>1M, resulting in Q<1 and Ecell
Tags
NGSS.HS-PS1-5
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The reaction represented by the equation above serves as the basis for the construction of an electrochemical cell. The table gives the reduction half-reactions and their respective standard reduction potentials. Based on the overall reaction, which type of electrochemical cell was constructed, and why?
A galvanic or voltaic cell, because the standard reduction potentials for the two half-reactions are positive and E°cell=0.80+0.34=+1.14V.
A galvanic or voltaic cell, because the standard reduction potentials for the two half-reactions are positive and E°cell=0.80−0.34=+0.46V
An electrolytic cell, because ΔG=−(96,500×(−0.46))/1000 =44kJ/mol and its operation requires a potential smaller than 0.46V to be supplied.
An electrolytic cell, because ΔG=−(2×96,500×(−0.46))/1000 = 89 kJ/mol and its operation requires a potential greater than 0.46V to be supplied.
Tags
NGSS.HS-PS1-4
NGSS.HS-PS3-1
NGSS.HS-PS1-2
5.
MATCH QUESTION
1 min • 1 pt
Match the following properties with their classification as either an intensive or extensive property.
Temperature at which an object changes from solid to liquid
Melting point
Amount of matter in an object
Metallic
Color of an object
Mass
Appearance of an object
Silver
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
The operation of a hydrogen fuel cell under standard conditions relies on the chemical reaction represented above. The table provides the relevant reduction half-reactions and the standard reduction potentials. Based on the information given, which of the following equations can be used to calculate the standard reduction potential, in volts, of the half-reaction occurring at the cathode?
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A galvanic cell was constructed using a salt bridge containing KNO3. A second cell is constructed from identical half-cells but uses NaNO3 for the salt bridge. Which of the following best explains whether the initial potential of the second cell will be different from the initial potential of the first cell?
The initial potential of the second cell will be lower than the initial potential of the first cell because Na has a lower molar mass than K has.
The initial potential of the second cell will be higher than the initial potential of the first cell because Na is less electronegative than K is.
The initial potential of the second cell will be the same as the first cell because the ions from the salt bridge are not oxidized or reduced during cell operation.
The initial potential of the second cell will be higher than the initial potential of the first cell because Na is less electronegative than K is.
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