
ET 4 Practice
Authored by Douglas Dehn
Chemistry
University
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19 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the correct order of increasing energy?
Microwaves, visible light, ultraviolet light, x-rays, γ-rays
Microwaves, x-rays, γ-rays, visible light, ultraviolet light
Microwaves, ultraviolet light, visible light, x-rays, γ-rays
X-rays, γ-rays, microwaves, visible light, ultraviolet light
Answer explanation
The correct order of increasing energy (E) is based on the electromagnetic spectrum. Microwaves have the lowest energy, followed by visible light, ultraviolet light, x-rays, and finally γ-rays, which have the highest energy.
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the correct order of increasing wavelength?
γ-rays, UV, X-rays, radio, infrared
γ-rays, X-rays, UV, infrared, radio
X-rays, microwaves, visible light, γ-rays, ultraviolet light
X-rays, γ-rays, microwaves, visible light, ultraviolet light
Answer explanation
The correct order of increasing wavelength (λ) is based on the electromagnetic spectrum.
γ-rays have the shortest wavelength (λ), followed by X-rays, UV, infrared (IR), and radio waves with the longest wavelength.
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the correct order of increasing velocity (v)?
Microwaves, visible light, ultraviolet light, x-rays, γ-rays
Microwaves, x-rays, γ-rays, visible light, ultraviolet light
Microwaves, ultraviolet light, visible light, x-rays, γ-rays
X-rays, γ-rays, microwaves, visible light, ultraviolet light
Answer explanation
The correct order of increasing velocity (v) is based on the electromagnetic spectrum. Microwaves have the lowest velocity, followed by visible light, ultraviolet light, x-rays, and finally γ-rays, which have the highest velocity.
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
If a photon’s wavelength is 663 nm, what is its energy?
4.40 x 10-37 J
3.00 x 10-22 J
4.40 x 10-40 J
3.00 x 10-19 J
Answer explanation
The energy of a photon can be calculated using the formula E = hc/λ. Here, h = 6.626 x 10-34 J·s, c = 3.00 x 108 m/s, and λ = 663 nm (or 663 x 10-9 m). This gives E ≈ 3.00 x 10-19 J, which is the correct answer.
Remember, both the speed of light (c = 3.00 x 108 m/s) and Planck's constant (h = 6.626 x 10-34 J·s) are provided on the Constants section of your Formula Chart. Also, notice that Dr. Laude made sure that the numeric value for wave length cancels out with Plank's Constant, meaning you know your answer must be 3.00 x 10? . Then it is just dividing exponents, which is addition and subtraction, to get you to your answer.
5.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
If a photon’s wavelength is 1328 nm, what is its energy?
2.20 x 10-22 J
1.50 x 10-22 J
2.20 x 10-19 J
1.50 x 10-19 J
Answer explanation
The energy of a photon can be calculated using the formula E = hc/λ. Here, h = 6.626 x 10-34 J·s, c = 3.00 x 108 m/s, and λ = 1328 nm (or 1328 x 10-9 m). This gives E ≈ 1.50 x 10-19 J, which is the correct answer.
Remember, both the speed of light (c = 3.00 x 108 m/s) and Planck's constant (h = 6.626 x 10-34 J·s) are provided on the Constants section of your Formula Chart. Also, notice that Dr. Laude made sure that the numeric value for wave length double Plank's Constant, meaning you know your answer must be 1.50 x 10? . Then it is just dividing exponents, which is addition and subtraction, to get you to your answer.
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
If a photon’s wavelength is 332 nm, what is its energy?
5.20 x 10-22 J
6.00 x 10-22 J
5.20 x 10-19 J
6.00 x 10-19 J
Answer explanation
The energy of a photon can be calculated using the formula E = hc/λ. Here, h = 6.626 x 10-34 J·s, c = 3.00 x 108 m/s, and λ = 332 nm (or 332 x 10-9 m). This gives E ≈ 6.00 x 10-19 J, which is the correct answer.
Remember, both the speed of light (c = 3.00 x 108 m/s) and Planck's constant (h = 6.626 x 10-34 J·s) are provided on the Constants section of your Formula Chart. Also, notice that Dr. Laude made sure that the numeric value for wave length half of Plank's Constant, meaning you know your answer must be 6.00 x 10? . Then it is just dividing exponents, which is addition and subtraction, to get you to your answer.
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
When a given molecule absorbs a photon of infrared (IR) radiation
It promotes electrons intro delocalized bonding orbitals.
It begins to vibrate.
It begins to rotate.
Its electrons are excited to higher energy levels.
Answer explanation
When a molecule absorbs infrared radiation, it primarily causes the bonds within the molecule to vibrate. This is the key interaction with IR radiation, making 'It begins to vibrate' the correct answer.
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