Continuous Growth and Decay Word Problems

From 2000 - 2010 a city had a 2.5% annual decrease in population. If the city had 2,950,000 people in 2000, determine the city’s population in 2008.

Round to the nearest..... (these are people)... so whole number!

You buy a car for $8000 that depreciates at a rate of 11% a year. How much is the car worth after 5 years?

Round to the nearest cent. (two decimal places)

P = 8(1.23)^t

Is the function growth or decay?

Check the box:

• Growth

• Decay

Nathan bought a VERY fancy boat for about $125,000. If the boat's value depreciates at the rate of 15% per year, what is the value of the boat at the end of 10 years?

• $12,512.50

• $18,750

• $24,609.30

• $505,694.72

Gasoline costs $1.99 per gallon. If the price per gallon increases an average of 6% per month, which function models the exponential growth of the pricing?

• 1.06(1.99)^t

• 1.99(1.06)^t

• [1.06(1.99)]^t

• 1.99(.94)^t

You buy a new computer for $2100. The computer decreases by 50% annually. How much is it worth after 2 years.

• $225

• $325

• $425

• $525

The population of Hickory NC, can be modeled by P=6191(1.04)t where t is the number of years since 1995. What was the population in 1995?

• 6191

• 1

• 1995

• 1.04

Classify the model as Exponential GROWTH or DECAY.
A=10(1.01)³

• Growth

• Decay

Daniel’s Print Shop purchased a new printer for $35,000. Each year it depreciates at a rate of 5%. How much will the printer be worth in 8 years?

• $23,219.72

• $136.72

• $51,710.94

• $16,710.94

A population of a city is 422,000 and increases by 12% each year. Use an exponential function to find the population of the city after 8 years.

• 100,144 people

• 1,083,024 people

• 1,044,856 people

• 200,000 people