Intro to Elimination Systems

What is the final step in the elimination method?

• Substitute the found value back into one of the original equations to solve for the other variable.

• Divide one of the equations by a constant.

• Multiply one of the equations by a constant.

• Add the two equations together.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations using the elimination method:

2x + 3y = 8

4x - 3y = 10

• x = 3

  y = 2/3

• x = 2

  y = 3

• x = 4

  y = -3

• x = 2

  y = -4/3

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations using the elimination method:

3x - 2y = 8

5x + 4y = 6

• x = -2

  y = -6

• x = 5

  y = 4

• x = 2

  y = -1

• x = 3

  y = -2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations using the elimination method:

2x + 5y = 9

3x - 5y = 1

• x = -8

  y = -5

• x = -8

  y = 5

• x = 2

  y = 1

• x = 1

  y = 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations using the elimination method:

4x - 3y = 5

2x + 3y = 1

• x = 1

  y = 1/3

• x = -1

  y = -1/3

• x = 1

  y = -1/3

• x = 0

  y = 0

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the following system of equations using the elimination method:

3x + 2y = 9

3x - 3y = 4

• x = 11/3

  y = 1

• x = 7/3

  y = 1

• no solution

• x = 35/3

  y = -13

Tags

CCSS.8.EE.C.8B

Solve the following system of equations:

3x - 4y = 12

6x - 8y = 16

• x = 13/2

  y = -15/8

• x = 5/2

  y = -9/8

• x = 8

  y = 3

• No Solution

Tags

CCSS.8.EE.C.8B

Solve by elimination:
4x+9y=28
-4x-y=-28

• (-7,0)

• (6,0)

• (-6,0)

• (7,0)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by elimination:
-9x-4y=-20

5x+4y=4

• (-4,4)

• (4,4)

• (4,-4)

• (-4,-4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system?

• (0, 3)

• (1, -1)

• (-3, 1)

• (1, 3)

Tags

CCSS.8.EE.C.8A