Solving Quadratic Equation with Zero on RHS

Solve by factoring

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Solve using the Quadratic Formula:

2x² + 2x − 12 = 0

• x = −2, 3

• x = 2, 3

• x = 2, −3

• x = −2, −3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. (HINT: Factor GCF 1st)

• x = 3, x = -6

• x = 0, x = 2

• x = 2, x = 3

• x = -2, x = 1

Tags

CCSS.HSA-REI.B.4B

Factor x²-11x+24

• (x-3)(x-8)

• (x-2)(x-12)

• (x+3)(x+8)

• (x+2)(x+12)

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }

• { -2, -3 }

• { 2, 3 }

• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

When using factoring to solve a quadratic equation, what must be true?

• The equation must be set equal to 1.

• The equation must be set equal to 10.

• The equation must be set equal to 0.

• It is not necessary to set the equation equal to anything.

Tags

CCSS.HSA-REI.B.4B

Which is in the proper factored form to use the Zero Product Property ?

Tags

CCSS.HSA-REI.B.4B

Given this graph is the function of y=x^2-2x-8 , what is the solution to x^2=2x+8 ?

• (1, 9)
  

• x = {-2, 4}
  

• (0, 8)
  

• x = {5, 2}
  

Solve by the method of your choice.

• x = 7 only
  

• x = 0 only
  

• x = 0 and 7
  

• There is no real answer for this equation.
  

Tags

CCSS.HSA-REI.B.4B

Suzanne solved the equation using this process.

Did she make a mistake?

If yes, at which line did she make her first mistake?

(There are 5 steps in her process)

• Suzanne made no errors.
  

• Step 2
  

• Step 3
  

• Step 4
  

• Step 5
  

Tags

CCSS.HSA.REI.A.1