Solving Quadratic Equations with Imaginary Roots

• A
• B
• C
• D

• A
• B
• C
• D

The discriminant is

• aX²  + bX  +  c

• b - 4ac

• b² - 4ac

• b² + 4ac

When does a quadratic equation have no real solutions?

• When you cannot factor it

• When it begins with a negative leading coefficient

• When the discriminant is negative

• When it only has two terms

Solve for x: 

• x = {-4, -1}

• x = {-1, -4}

• x = {2+i, 2-i}

• x = {-2+i, -2-i}

Determine the roots of the quadratic equation 7x^2 + 28 = 0 using square roots with imaginary numbers.

• x = 2

• x = 4i

• x = -2

• The roots of the quadratic equation 7x^2 + 28 = 0 are x = 2i and x = -2i.

Solve for x: 3x² - 6x + 6 = 0

• x = 1± i

• x = 3, -6

• x = 4.8, 2.7

• Undefined

Find the roots of the equation 5x^2 + 20 = 0 using imaginary numbers.

• x = ±3i

• x = ±4i

• x = ±2i

• x = ±5i

What are the roots of the quadratic equation 3x^2 + 12 = 0?

• x = ±2

• x = ±2i

• x = ±4

• x = ±3i

Find the solutions of the quadratic equation x^2 + 4 = 0.

• x = 1, x = -1

• x = 2, x = -2

• x = 2i, x = -2i

• x = 4i, x = -4i