Solving Systems of Linear Equations

What is the first step in solving a system of equations by elimination/matrices?

• Get both equations in standard form and line up the like terms.

• Get both equations in slope-intercept form.

• Get both equations equal to zero.

• Put the x terms first.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Is (1,10) a solution to

y=7x+5

y=x+9

• yes

• no

what does the top equation need to be multiplied by to create a zero pair?

2x - 6y = 20

2x + 5y = -11

• -1

• 1

• -2

• 2

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What action can you take to create equivalent coefficients so that the "elimination" method can be used?

• Multiply the top equation by 4

• Multiply the top equation by 2

• Multiply the bottom equation by 2

• Multiply the bottom equation by 4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution of the system of equations y = 3x - 1 and y = -2x + 4?

• (0, 0)

• (1, 2)

• (2, 1)

• (3, 3)

Tags

CCSS.8.EE.C.8B

What is the first step in solving a system of equations by substitution?

• Add the equations together

• Substitute the value of one variable into the other equation

• Multiply both equations by a number

• Graph the equations

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

How many solutions will this system have? 

• No solution

• One Solution

• I Don't Know

• Infinitely Many Solutions

Tags

CCSS.8.EE.C.8A

The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. The school took in $52 on the second day by selling 3 senior citizen tickets and 2 child tickets. Which equations represents the system that could be used?

• 1s + 3c = 38
  2s + 3c = 52

• 3s + 1c = 38
  3s + 2c = 52

• s + c = 38
  s + c = 52

• 3s + 3c = 38
  1s + 2c = 52

Tags

CCSS.HSA.CED.A.3

How many solutions will this system have?

• One

• Two

• No Solution

• Infinitely Many Solutions

Tags

CCSS.8.EE.C.8B

Solve the system by substitution.
 
5x + 4y= −14
y =  −7x  −  15 

• (-2, -1)

• (1, -2)

• (-2, 1)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6