Write Systems of Linear Equations

Quiz
•
Mathematics
•
9th Grade
•
Hard
+1
Standards-aligned
Anthony Clark
FREE Resource
15 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A
B
C
D
Tags
CCSS.HSA.CED.A.3
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
f + t = 72
7t + 3f = 12
t + f = 12
3t + 7f = 72
t + f = 12
7t + 3f = 72
t + f = 12
10 ( t + f ) = 72
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Tags
CCSS.8.EE.C.8C
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A large pizza at Palanzio’s Pizzeria costs $6.80 plus $0.90 for each topping. The cost of a large cheese pizza at Guido’s Pizza is $7.30 plus $0.65 for each topping. Which system of equations could be used to find the number of toppings when both companies cost the same amount?
y = 6.80 + .65x
y=7.30+.90x
x + y = 6.80
x + y = 7.30
y = 6.80+.90x
y = 7.30 + .65x
y + .90x = 6.80
y + .65x = 7.30
Tags
CCSS.HSA.CED.A.3
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
At a college bookstore, Carla purchased a math textbook and a novel that cost a total of $54, not including tax. If the price of the math textbook, t, is $8 more than 3 times the price of the novel, n, which system of linear equations could be used to determine the price of each book?
t + n = 54
t = 3n + 8
t + n = 54
n = 3t + 8
t + n = 54
t = 3n - 8
t + n = 8
t = 3n + 54
Tags
CCSS.HSA.CED.A.3
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A total of 1,650 boxes of cookies were sold last week by a group of Girls Scouts. Each large box of cookies cost $3.50, and each small box of cookies cost $2.00. The Girl Scouts group earned $4,650. Which of the following systems of equations could be used to determine, l, the number of large boxes of cookies, and s, the number of small boxes of cookies sold?
3.50l + 2.00s = 4,650
l + s = 1,650
3.50l – 2.00s = 4,650
l + s = 1,650
3.50l + 2.00s = 1,650
l + s = 4,650
3.50s + 2.00l = 1,650
l – s = 4,650
Tags
CCSS.HSA.CED.A.3
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Which system of two linear equations in two variables best represents the graph?
y = 3x – 3
y = -2x + 7
y = 2x – 3
y = -3x + 7
y = 2x + 3
y = -3x + 3.5
y = 7x + 3.5
y = x – 3
Tags
CCSS.8.EE.C.8B
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